Symmetry Constraint on Charged Particle Geometry

In working out the details of how the complex unitary twist field would work on a system of two charged particles, I came across a very important discovery.  This holds true even if you don’t believe in the unitary twist field theory tooth fairy, even if you only think in terms of QFT virtual particles.

If you have two identical charged particles such as electrons separated by a distance r, symmetry geometry requires that the interaction cannot be static.  Any continuous static field in this system must have a plane perpendicular to the path between the particles that is the same as if there were no particles–that is, identical to the background field.  For standard QFT, this plane cannot have an electrostatic potential relative to the field out at infinity.  For the Complex Unitary Twist Field theory, this plane must be at the background field state in the imaginary dimension.

 

But if this is true, then that becomes a point where the behavior of one particle cannot affect the other–there is no field potential.  I won’t go into the QFT case, but the analogy is similar when I try to work a geometric solution in the twist field case.  I had found a way that the bend of the twist field imaginary background vector would specify the effect of charge on the second particle.  But this bend has to be symmetric in this system, with a plane in the middle where the bend is the same as the overall background field with no charges.  Oops–the problem shows up where there is no way to communicate the bend effect to the second particle without creating a paradox–an impossible field situation.

 

Any static field between two identical charged particles must have a plane between them that cannot pass the charge effect. The charge effect must pass dynamically across this plane

I said, uh-oh–the unitary twist field can’t work this way with bends.  Then I realized this has to be true for QFT too!  The symmetry of the system says that there is no way that the charged particle force can be conveyed within a static field.  There has to be something dynamic passing through the plane–virtual photons for QFT, and probably some type of background vector motion for the unitary twist field.  These two theories have to converge, and symmetry is going to severely constrain what has to be happening across the plane.  Even if you ignore unitary twist field theory, and just make the statement that QFT claims that virtual photons are not real (and unitary twist field theory specifies virtual photons as partial field twists that don’t complete but revert back to the background vector state), this symmetry problem forces the virtual photons to have both a physical field property and a property of motion.

Agemoz

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