Speed of Light

My previous post showed how the unitary field twist would work and not contradict the findings that no lumniferous ether can be observed. The second stage of checking the validity of the unitary field twist theory to real life is to show how the speed of light will be the same in every frame of reference.

The unitary twist field theory has linear twists (photons) and circular twist solitons (electrons/positrons). Presumably other self-contained twist geometries would give other particles. However, for this case, let’s assume that a system of electrons moving with a frame of reference can detect the speed of a photon, and let’s pick any arbitrary frame of reference to be an absolute reference frame for the unitary twist field. I can show that regardless of the chosen frame of reference, the system of electrons will think that the photon is moving at the same speed as the absolute reference frame–that is, in all frames of reference, the speed of light is the same. This can be seen when you realize that the twist ring that represents the electron has an implied clock that equals the rate at which it spins. This twist ring, when moved, must still have the path, which now becomes a spiral, limited to the speed of light in the absolute frame of reference. This causes the “clock”, the spin rate of the twist, to slow down when observed from the absolute frame of reference–so when measuring the time taken for the photon to travel from point A to B, in the frame of reference of the system of electrons, time should slow down by exactly the amount that would make it appear that in that frame of reference, the photon was moving at the speed of light.

Of course, the assumption here is that the spiral spin rate really corresponds to the apparent clock or time passage variation sensed by the system of electrons. I need to think about this to see if I really buy that, but with that assumption, I see how the apparent constant speed of light in all frames of reference results from the geometry of a speed limit of light in one particular frame of reference. It actually doesn’t matter which frame of reference we pick as the “absolute” frame of reference, any will do. From this and the fact that rings turn into spirals in such a way to affect its spin rate and hence apparent clock time, ring twists will always observe linear twists as having the same speed regardless of the frame of reference of either the observing system of electrons or the photon.

OK, let’s look at this in more detail–it’s actually pretty easy to see how this works. As mentioned, create an imaginary system where two electron “clocks” are spaced at points A and B in a frame of reference we will call the absolute frame. Now shoot a photon from A to B with the intent of measuring how fast it goes. In our absolute frame of reference, we know the distance between A and B and the difference in the electron clock times (that is, electron twist ring cycles, and thus can compute the speed of light in this frame of reference. For convenience, let’s set the distance from A to B to be one electron ring cycle.

Now, let’s take this whole system and put it in a frame of reference that is moving in the direction from A to B. We will have the electron clocks be part of that system, but point B, and the photon, and the electron clock triggers, will all be moving with the new frame of reference. (Why not point A? because in both frames we can set things up so that the time and distance measurements have the same start point, with no loss of generality). OK, first, what do we see in our absolute frame? The same thing we saw before, since the only thing that is changing is the behavior of the electron clocks, which, in the moving frame, now look like a spiral to us in the absolute frame and will look like it takes longer to complete a cycle. To us, these clocks look like they are running slow proportionate to the velocity of the moving frame. There are two cases to consider, the photon travelling in the same direction as the velocity vector of the new frame, and the second case traveling in the opposite direction. Consider the first case. Here, point B in the moving frame will move away from A, making the distance that the photon travels longer proportionate to the velocity of the new frame (from the point of view of our absolute frame). But–the apparent time (seen from the absolute frame) that has passed before the photon hits the moving frame point B will also will seem to be longer since the electron clock at point b is not a ring but a spiral–and since in the absolute frame the electron clock spiral edge is limited to speed c, the apparent time passing will be proportionate to the velocity of the new frame (unroll one cycle of the spiral, you will get a right triangle and the hypotenuse will vary proportionately to the frame velocity edge v. The hypotenuse transit time will vary from the ring transit time proportionate to v.

Now take the case where the photon measurement moves opposite the velocity of the new frame. In this case, point B will appear to be moving closer to point A in the absolute frame, so the photon will get to point B more quickly. However, the clock will also be abbreviated since the time it measures will be proportionate to the abbreviated path. No matter what the frame velocity is and the corresponding distance the photon has to travel, the clock will also rotate proportionately. The observed passage of time and the distance traveled will have a constant ratio–the apparent speed of light will remain the same in any frame of reference.

Pretty fascinating! I still have work to do to prove this is generally true–but it’s an interesting consequence of the twist ring geometry that seems to have a real-life connection–the constant speed of light in all frames of reference that is declared by the special theory of relativity.

Agemoz

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